BigDecimalLiteralDouble
BigDecimal(double) and BigDecimal.valueOf(double) may lose precision, prefer BigDecimal(String) or BigDecimal(long)

Category

Severity

WARNING

Maturity

The problem

BigDecimal has a two mechanisms for converting a double into a BigDecimal, new
BigDecimal(double), and BigDecimal.valueOf(double). These methods are a possible
source of precision loss if the number does not have an exact double
representation. The new BigDecimal(String) and new BigDecimal(long) constructors
should be prefered, as they do not require using a lossy argument.

For example 0.1 cannot be exactly represented a double. Thus
new BigDecimal(.1) represents the same bignum as
new BigDecimal("0.1000000000000000055511151231257827021181583404541015625")
and not `new BigDecimal(“.1”).

Suppression

Suppress false positives by adding an @SuppressWarnings("BigDecimalLiteralDouble") annotation to the enclosing element.